If you try to open a file that is not a ZIP file, the exception
zipfile.BadZipFile is raised.
In Python 2.7, this was spelled
zipfile.BadZipfile, and this old name is retained alongside the new one in Python 3.2+
To start, import the
zipfile module, and set the filename.
import zipfile filename = 'zipfile.zip'
Working with zip archives is very similar to working with files, you create the object by opening the zipfile, which lets you work on it before closing the file up again.
zip = zipfile.ZipFile(filename) print(zip) # <zipfile.ZipFile object at 0x0000000002E51A90> zip.close()
In Python 2.7 and in Python 3 versions higher than 3.2, we can use the
with context manager. We open the file in "read" mode, and then print a list of filenames:
with zipfile.ZipFile(filename, 'r') as z: print(zip) # <zipfile.ZipFile object at 0x0000000002E51A90>
There are a few ways to inspect the contents of a zipfile. You can use the
printdir to just get a variety of information sent to
with zipfile.ZipFile(filename) as zip: zip.printdir() # Out: # File Name Modified Size # pyexpat.pyd 2016-06-25 22:13:34 157336 # python.exe 2016-06-25 22:13:34 39576 # python3.dll 2016-06-25 22:13:34 51864 # python35.dll 2016-06-25 22:13:34 3127960 # etc.
We can also get a list of filenames with the
namelist method. Here, we simply print the list:
with zipfile.ZipFile(filename) as zip: print(zip.namelist()) # Out: ['pyexpat.pyd', 'python.exe', 'python3.dll', 'python35.dll', ... etc. ...]
namelist, we can call the
infolist method, which returns a list of
ZipInfo objects, which contain additional information about each file, for instance a timestamp and file size:
with zipfile.ZipFile(filename) as zip: info = zip.infolist() print(zip.filename) print(zip.date_time) print(info.file_size) # Out: pyexpat.pyd # Out: (2016, 6, 25, 22, 13, 34) # Out: 157336
Extract all file contents of a zip file
import zipfile with zipfile.ZipFile('zipfile.zip','r') as zfile: zfile.extractall('path')
If you want extract single files use extract method, it takes name list and path as input parameter
import zipfile f=open('zipfile.zip','rb') zfile=zipfile.ZipFile(f) for cont in zfile.namelist(): zfile.extract(cont,path)
To create new archive open zipfile with write mode.
import zipfile new_arch=zipfile.ZipFile("filename.zip",mode="w")
To add files to this archive use write() method.
new_arch.write('filename.txt','filename_in_archive.txt') #first parameter is filename and second parameter is filename in archive by default filename will taken if not provided new_arch.close()
If you want to write string of bytes into the archive you can use writestr() method.
str_bytes="string buffer" new_arch.writestr('filename_string_in_archive.txt',str_bytes) new_arch.close()